¡¾ÌâÄ¿¡¿Ò»¶¨Î¶ÈÏ£¬ÏòÈÝ»ýΪV LµÄºãÈÝÃܱÕÈÝÆ÷ÖÐͨÈë1 mol CH3Cl(g)ºÍ1 mol H2O(g)£¬ÌåϵÄÚͬʱ´æÔÚÏÂÁÐÁ½¸öƽºâ£º

·´Ó¦¢Ù£ºCH3Cl(g)£«H2O(g)CH3OH(g)£«HCl(g) K1

·´Ó¦¢Ú£º2CH3OH(g)(CH3)2O(g)£«H2O(g) K2

·´Ó¦t minºóÌåϵ´ïµ½Æ½ºâ£¬´Ëʱ(CH3)2O(g)µÄÎïÖʵÄÁ¿Îª9¡Á10-3mol£¬CH3Cl(g)µÄƽºâת»¯ÂÊΪ4.8%£¬»Ø´ðÏÂÁÐÎÊÌ⣺

(1)0¡«t minÄÚ£¬CH3Cl(g)µÄ·´Ó¦ËÙÂÊΪ___________¡£

(2)·´Ó¦´ïµ½Æ½ºâʱ£¬CH3OH(g)µÄÎïÖʵÄÁ¿Îª___________¡£

(3)¼ÆËã·´Ó¦¢ÚµÄƽºâ³£ÊýK2£½___________¡£

(4)µ±·´Ó¦µ½´ïƽºâʱ£¬ÔÙÏòÌåϵÄÚͨÈëÒ»¶¨Á¿µÄCH3OH(g)£¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ________(Ìî×Öĸ)¡£

A.·´Ó¦¢ÙµÄƽºâÄæÏòÒƶ¯£¬·´Ó¦¢ÚµÄƽºâ²»·¢ÉúÒƶ¯

B.ƽºâʱ·´Ó¦¢Ù¡¢·´Ó¦¢ÚµÄ·´Ó¦ËÙÂʶ¼Ôö´ó

C.K1Ôö´ó£¬K2¼õС

¡¾´ð°¸¡¿molL-1min-1 0.03mol 9.61 B

¡¾½âÎö¡¿

Ò»¶¨Î¶ÈÏ£¬ÏòÈÝ»ýΪV LµÄºãÈÝÃܱÕÈÝÆ÷ÖÐͨÈë1 mol CH3Cl(g)ºÍ1 mol H2O(g)£¬ÌåϵÄÚͬʱ´æÔÚÏÂÁÐÁ½¸öƽºâ£º

·´Ó¦¢Ù£ºCH3Cl(g)£«H2O(g)CH3OH(g)£«HCl(g) K1

·´Ó¦¢Ú£º2CH3OH(g)(CH3)2O(g)£«H2O(g) K2

·´Ó¦´ïµ½Æ½ºâʱҪ¿¼Âǵ½CH3OH(g)µÄŨ¶ÈÊÇÁ½¸ö»¯Ñ§·´Ó¦×ۺϺóµÃµ½µÄ½á¹û¡£

£¨1£©·´Ó¦¿ªÊ¼Ê±£¬CH3Cl(g)Ϊ1 mol£¬t minºóCH3Cl(g)µÄƽºâת»¯ÂÊΪ4.8%£¬ËùÒÔCH3Cl(g)µÄÎïÖʵÄÁ¿±ä»¯Á¿Îª1mol4.8%=0.048mol£¬»¯Ñ§·´Ó¦ËÙÂÊ===molL-1min-1£¬¹Ê´ð°¸ÎªmolL-1min-1£»

£¨2£©ÌåϵÖÐÁ½¸ö·´Ó¦Í¬Ê±·¢Éú£¬ÓÉ·´Ó¦¢ÙCH3Cl(g)µÄÎïÖʵÄÁ¿±ä»¯Á¿Îª0.048mol£¬¿ÉÖª¹²Éú³ÉCH3OH(g)µÄÎïÖʵÄÁ¿Îª0.048mol£¬ÓÉ·´Ó¦¢ÚÖÐ(CH3)2O(g)µÄÎïÖʵÄÁ¿Îª9¡Á10-3mol£¬¿ÉÖªÏûºÄµÄCH3OH(g)µÄÎïÖʵÄÁ¿Îª9¡Á10-3mol¡Á2=0.018mol£¬ËùÒÔ·´Ó¦´ïµ½Æ½ºâʱ£¬CH3OH(g)µÄÎïÖʵÄÁ¿Îª0.048mol-0.018mol=0.03mol£¬¹Ê´ð°¸Îª0.03mol£»

£¨3£©·´Ó¦¢Ù´ïµ½Æ½ºâºóûÓвμӷ´Ó¦µÄH2O(g)µÄÎïÖʵÄÁ¿Îª1mol-0.048mol=0.952mol£¬·´Ó¦¢ÚÉú³ÉµÄH2O£¨g£©µÄÎïÖʵÄÁ¿Îª9¡Á10-3mol£¬ËùÒÔƽºâʱÈÝÆ÷ÄÚH2O£¨g£©µÄÎïÖʵÄÁ¿Å¨¶ÈΪ= molL-1£¬(CH3)2O(g)µÄÎïÖʵÄÁ¿Å¨¶ÈΪ=molL-1£¬ÓÉ£¨2£©¿É֪ƽºâʱCH3OH(g)µÄÎïÖʵÄÁ¿Å¨¶ÈΪ= molL-1£¬Æ½ºâ³£ÊýK2£½=9.61£¬¹Ê´ð°¸Îª9.61£»

£¨4£©µ±·´Ó¦µ½´ïƽºâʱ£¬ÔÙÏòÌåϵÄÚͨÈëÒ»¶¨Á¿µÄCH3OH(g)£¬CH3OH(g)ÎïÖʵÄÁ¿Å¨¶ÈÔö´ó£¬·´Ó¦¢ÙµÄƽºâÄæÏòÒƶ¯£¬·´Ó¦¢ÚµÄƽºâÕýÏòÒƶ¯£¬Æ½ºâʱ·´Ó¦¢Ù¡¢·´Ó¦¢ÚµÄ·´Ó¦ËÙÂʶ¼Ôö´ó£¬Î¶Ȳ»±äʱ£¬·´Ó¦µÄƽºâ³£Êý¶¼²»¸Ä±ä£¬¹Ê´ð°¸Ñ¡B¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿¹¤Òµ·ÏÆø¡¢Æû³µÎ²ÆøÅŷųöµÄNOx¡¢SO2µÈ£¬ÊÇÐγÉÎíö²µÄÖ÷ÒªÎïÖÊ£¬Æä×ÛºÏÖÎÀíÊǵ±Ç°ÖØÒªµÄÑо¿¿ÎÌâ¡£

£¨1£©ÒÑÖª£º¢ÙCOȼÉÕÈȵġ÷H1=£­283.0kJ¡¤mol-l£¬¢ÚN2(g)+O2(g) 2NO(g) ¡÷H2=+180.5kJ¡¤mol-1£¬Æû³µÎ²ÆøÖеÄNO(g)ºÍCO(g)ÔÚÒ»¶¨Î¶Ⱥʹ߻¯¼ÁÌõ¼þÏ¿ɷ¢ÉúÈçÏ·´Ó¦£º2NO(g)+2CO(g) N2(g)+2CO2(g)£» ¡÷H=___¡£

£¨2£©½«0£®20mol NOºÍ0£®10molCO³äÈëÒ»¸öÈÝ»ýºã¶¨Îª1LµÄÃܱÕÈÝÆ÷Öз¢ÉúÉÏÊö·´Ó¦£¬·´Ó¦¹ý³ÌÖв¿·ÖÎïÖʵÄŨ¶È±ä»¯ÈçÏÂͼËùʾ£®

¢Ù¸Ã·´Ó¦µÚÒ»´Î´ïµ½Æ½ºâʱµÄƽºâ³£ÊýΪ________¡£

¢ÚµÚ12minʱ¸Ä±äµÄÌõ¼þÊÇ________¡£

¢ÛÔÚµÚ24minʱ£¬Èô±£³ÖζȲ»±ä£¬ÔÙÏòÈÝÆ÷ÖгäÈëCOºÍN2¸÷0£®060mol£¬Æ½ºâ½«________Òƶ¯(Ìî¡°ÕýÏò¡±¡¢¡°ÄæÏò¡±»ò¡°²»¡±)£®

(3)SNCR-SCRÍÑÏõ¼¼ÊõÊÇÒ»ÖÖÐÂÐ͵ijýÈ¥ÑÌÆøÖеªÑõ»¯ÎïµÄÍÑÏõ¼¼Êõ£¬Ò»°ã²ÉÓð±Æø»òÄòËØ¡£

¢ÙSNCRÍÑÏõ¼¼ÊõÖУºÔÚ´ß»¯¼Á×÷ÓÃÏÂÓÃNH3×÷»¹Ô­¼Á»¹Ô­NO£¬ÆäÖ÷Òª·´Ó¦Îª£º4NH3(g)+4NO(g)+O2(g)=4N2(g)+6H2O(g)£¬¡÷H<0¡£ÌåϵζÈÖ±½ÓÓ°ÏìSNCR¼¼ÊõµÄÍÑÏõЧÂÊ£¬ÈçͼËùʾ¡£µ±ÌåϵζÈԼΪ925¡æʱ£¬SNCRÍÑÏõЧÂÊ×î¸ß£¬Æä¿ÉÄܵÄÔ­ÒòÊÇ________¡£

¢ÚSCRÍÑÏõ¼¼ÊõÖÐÔòÓÃÄòËØ[CO(NH2)2]×÷»¹Ô­¼Á»¹Ô­NO2µÄ»¯Ñ§·½³ÌʽΪ____________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿ÏÖÓÐÒ»¶¨Á¿º¬ÓÐNa2OÔÓÖʵÄNa2O2ÊÔÑù£¬ÓÃÏÂͼµÄʵÑé×°ÖòⶨNa2O2ÊÔÑùµÄ´¿¶È¡£(¿É¹©Ñ¡Óõķ´Ó¦ÎïÖ»ÓÐCaCO3¹ÌÌå¡¢6 mol¡¤L£­1ÑÎËá¡¢6 mol¡¤L£­1ÁòËáºÍÕôÁóË®)

»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©°´ÈçͼËùʾµÄ×°ÖÃÁ¬½ÓÍêÒÇÆ÷£¬ÔÚ¼ÓҩƷ֮ǰӦ¸Ã×öµÄ²Ù×÷ÊÇ______________

£¨2£©×°ÖÃAÖÐÒºÌåÊÔ¼ÁÑ¡ÓÃ_____________________________£¬

£¨3£©×°ÖÃBµÄ×÷ÓÃÊÇ___________________________________£¬×°ÖÃCµÄ×÷ÓÃÊÇ____________________________________£¬×°ÖÃEÖмîʯ»ÒµÄ×÷ÓÃÊÇ____________________________________________£¬

£¨4£©×°ÖÃDÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ______________________________________

£¨5£©Èô¿ªÊ¼Ê±²âµÃÑùÆ·µÄÖÊÁ¿Îª2.0 g£¬·´Ó¦½áÊøºó²âµÃÆøÌåÌå»ýΪ224 mL(±ê×¼×´¿ö)£¬ÔòNa2O2ÊÔÑùµÄ´¿¶ÈΪ________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ

A.°´ÏµÍ³ÃüÃû·¨£¬»¯ºÏÎïµÄÃû³ÆÊÇ2£¬3£¬5£¬5£­Ëļ׻ù£­4£¬4£­¶þÒÒ»ù¼ºÍé

B.µÈÎïÖʵÄÁ¿µÄ±½ºÍ±½¼×ËáÍêȫȼÉÕÏûºÄÑõÆøµÄÁ¿²»ÏàµÈ

C.±½ºÍ¼×±½»¥ÎªÍ¬ÏµÎ¾ùÄÜʹKMnO4ËáÐÔÈÜÒºÍÊÉ«

D.½á¹¹Æ¬¶ÎµÄ¸ß¾ÛÎÆäµ¥ÌåÊDZ½·ÓºÍ¼×È©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿ÄÉÃ×̼Ëá¸Æ¹ã·ºÓ¦ÓÃÓÚÏ𽺡¢ËÜÁÏ¡¢ÔìÖ½¡¢»¯Ñ§½¨²Ä¡¢ÓÍÄ«¡¢Í¿ÁÏ¡¢Ãܷ⽺Ó뽺ճ¼ÁµÈÐÐÒµ¡£ÔÚŨCaCl2ÈÜÒºÖÐͨÈëNH3ºÍCO2£¬¿ÉÒÔÖƵÃÄÉÃ×¼¶Ì¼Ëá¸Æ¡£Ä³Ð£Ñ§ÉúʵÑéС×éÉè¼ÆÏÂͼËùʾװÖã¬ÖÆÈ¡¸Ã²úÆ·¡£DÖÐ×°ÓÐպϡÁòËáµÄÍÑÖ¬ÃÞ£¬Í¼ÖмгÖ×°ÖÃÒÑÂÔÈ¥¡£

¢ñ£®¿ÉÑ¡ÓõÄÒ©Æ·ÓУº

a£®Ê¯»Òʯ£»b£®±¥ºÍÂÈ»¯¸ÆÈÜÒº£»c£®6 mol/LÑÎË᣻d£®ÂÈ»¯ï§£»e£®ÇâÑõ»¯¸Æ

£¨1£©AÖÐÖƱ¸ÆøÌåʱ£¬ËùÐèÒ©Æ·ÊÇ£¨Ñ¡Ìî×ÖĸÐòºÅ£©______________£»

£¨2£©BÖÐÊ¢Óб¥ºÍ̼ËáÇâÄÆÈÜÒº£¬Æä×÷ÓÃÊÇ______________________________£»

£¨3£©Ð´³öÖÆÈ¡°±ÆøµÄ»¯Ñ§·½³Ìʽ__________________________________£»

£¨4£©ÔÚʵÑé¹ý³ÌÖУ¬ÏòCÖÐͨÈëÆøÌåÊÇÓÐÏȺó˳ÐòµÄ£¬Ó¦ÏÈͨÈëÆøÌåµÄ»¯Ñ§Ê½______________£»

£¨5£©¼ìÑéD³ö¿Ú´¦ÊÇ·ñÓа±ÆøÒݳöµÄ·½·¨ÊÇ__________________________£»

£¨6£©Ð´³öÖÆÄÉÃ×¼¶Ì¼Ëá¸ÆµÄ»¯Ñ§·½³Ìʽ______________________________¡£

£¨7£©ÈôʵÑé¹ý³ÌÖÐÓа±ÆøÒݳö£¬Ó¦Ñ¡ÓÃÏÂÁÐ_____________×°ÖûØÊÕ£¨Ìî´úºÅ£©¡£

¢ò£®¾­·ÖÎöÔÚÉÏÊöÂÈ»¯ï§ÑùÆ·Öк¬ÓÐÔÓÖÊ̼ËáÇâÄÆ¡£ÎªÁ˲ⶨÂÈ»¯ï§µÄÖÊÁ¿·ÖÊý£¬¸ÃѧÉúʵÑéС×éÓÖÉè¼ÆÁËÈçÏÂʵÑéÁ÷³Ì£º

ÊԻشð£º

£¨1£©Ëù¼ÓÊÔ¼ÁAµÄ»¯Ñ§Ê½Îª______________________________________£»

£¨2£©B²Ù×÷·½·¨ÊÇ_______________________________________________£»

£¨3£©ÑùÆ·ÖÐÂÈ»¯ï§µÄÖÊÁ¿·ÖÊýΪ___________________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿ÒÑÖªÈçÏÂÁ½¸öÈÈ»¯Ñ§·´Ó¦

(l)£«H2(g)¡ú(l)H£¾0 ¢Ù

(l)£«2H2(g)¡ú(l)H£¼0 ¢Ú

ÏÂÁÐ˵·¨²»ÕýÈ·µÄÊÇ

A.·´Ó¦¢Ù¡¢¢Ú¶¼ÊôÓڼӳɷ´Ó¦

B.l£¬3Ò»»·¼º¶þÏ©±È±½Îȶ¨

C.·´Ó¦¢Ù¡¢¢ÚµÄÈÈЧӦ˵Ã÷±½»·Öк¬ÓеIJ¢²»ÊÇ̼̼˫¼ü

D.·´Ó¦¢Ù¡¢¢ÚÖеÄËùÓÐÓлúÎï¾ù¿ÉʹäåË®ÍÊÉ«£¬µ«ÍÊÉ«Ô­Àí²»ÍêÈ«Ïàͬ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿Ì¼ÊÇÐγɻ¯ºÏÎïÖÖÀà×î¶àµÄÔªËØ£¬Æäµ¥Öʼ°ÐγɵĻ¯ºÏÎïÊÇÈËÀàÉú²úÉú»îµÄÖ÷ÒªÄÜÔ´ÎïÖÊ¡£

(1)ÓлúÎïM¾­¹ýÌ«Ñô¹â¹âÕÕ¿Éת»¯³ÉÎïÖÊN£¬ÆäÄÜÁ¿±ä»¯ÈçͼËùʾ¡£ÔòM¡¢NÏà±È£¬½ÏÎȶ¨µÄÊÇ________(Ìî¡°M¡±»ò¡°N¡±)¡£

(2)ÒÑÖª£º

C(s)£«H2O(l)£½CO(g)£«H2(g) ¡÷H1£½a kJ¡¤mol-1

2CO(g)£«O2(g)£½2CO2(g) ¡÷H2£½b kJ¡¤mol-1

2H2(g)£«O2(g)£½2H2O(l) ¡÷H3£½c kJ¡¤mol-1

ÔòC(s)£«O2(g)£½CO2(g) ¡÷H£½______(ÓÃa¡¢b¡¢c±íʾ)kJ¡¤mol-1¡£

(3)¸ù¾Ý¼üÄÜÊý¾Ý¹ÀËãCH4(g)£«4F2(g)£½CF4(g)£«4HF(g)µÄ·´Ó¦ÈÈ¡÷H£½_________¡£

»¯Ñ§¼ü

C-H

C-F

H-F

F-F

¼üÄÜ(KJmol-1)

414

489

565

155

(4)ÔÚÒ»ºãÈݵÄÃܱÕÈÝÆ÷ÖУ¬¼ÓÈë1 mol CO(g)¡¢2 mol H2O(g)£¬·¢Éú·´Ó¦CO(g)£«H2O(g) H2(g)£«CO2(g) ¡÷H£¬COµÄƽºâת»¯ÂÊËæζȵı仯ÈçͼËùʾ¡£

¢Ù¸Ã·´Ó¦µÄ¡÷H________(Ìî¡°<¡±»ò¡°>¡±)0¡£

¢ÚÔÚÌå»ý²»±äʱ£¬ÒªÔö´ó¸Ã·´Ó¦µÄÕý·´Ó¦ËÙÂʿɲÉÈ¡µÄ´ëÊ©ÊÇ_________(ÈÎдһÌõ)¡£

¢ÛAµãʱ¸Ã·´Ó¦µÄƽºâ³£ÊýΪ___________(¾«È·µ½0.01)¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿ÓÐÏÂÁÐÈýÖÖÓлúÎʵÏÖËüÃÇÖ®¼äÏ໥ת»¯ËùÑ¡ÊÔ¼Á£¨¾ù×ãÁ¿£©ÕýÈ·µÄÊÇ£¨ £©

Ñ¡Ïî

aת»¯Îªb

aת»¯Îªc

cת»¯Îªb

A

NaOH

Na

CO2

B

Na2CO3

NaOH

HCl

C

NaHCO3

NaOH

CO2

D

NaHCO3

NaCl

HCl

A.AB.BC.CD.D

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿¸ù¾ÝÏÂÁÐʵÑéÄܵóöÏàÓ¦½áÂÛµÄÊÇ

Ñ¡Ïî

ʵÑé

½áÂÛ

A

³£ÎÂÏÂ,²âµÃ0.1mol/LNaAÈÜÒºµÄpHСÓÚ0.1mol/L Na2CO3ÈÜÒºµÄpH

ËáÐÔ:HA>H2CO3

B

Ïòº¬Óеí·ÛµÄFeI2ÈÜÒºÖмÓÈë×ãÁ¿äåË®,ÈÜÒº±äÀ¶É«

»¹Ô­ÐÔ:I->Fe2+

C

Ïò±¥ºÍFeSO4ÈÜÒºÖмÓÈëCuS¹ÌÌå,²âµÃÈÜÒºÖÐc(Fe2+)²»±ä

Ksp(CuS)<Ksp(FeS)

D

Ïò°±Ë®ÖеμÓÉÙÁ¿AgNO3ÈÜÒº£¬ÎÞ³ÁµíÉú³É

Ag+ÓëNH3¡¤H2OÄÜ´óÁ¿¹²´æ

A. A B. B C. C D. D

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸