£¨12·Ö£©Íê³ÉÒÔÏÂʵÑ飺¢ÙÓÃÓÒͼËùʾµÄ×°ÖÃÖÆÈ¡äåÒÒÍ飻¢Ú½øÐÐäåÒÒÍéµÄÐÔÖÊʵÑé¡£ÔÚÊÔ¹ÜIÖÐÒÀ´Î¼ÓÈë2 mL ÕôÁóË®¡¢4 mLŨÁòËá¡¢2 mL 95£¥µÄÒÒ´¼ºÍ3gä廯ÄÆ·ÛÄ©£¬ÔÚÊԹܢòÖÐ×¢ÈëÕôÁóË®£¬ÔÚÉÕ±­ÖÐ×¢Èë×ÔÀ´Ë®¡£¼ÓÈÈÊÔ¹ÜIÖÁ΢·Ð״̬Êý·ÖÖÓºó£¬ÀäÈ´¡£ÊԻشðÏÂÁÐÎÊÌ⣺

£¨1£©ÊÔ¹ÜIÖÐŨÁòËáÓëä廯ÄƼÓÈÈ·´Ó¦Éú³ÉÇâäåËᣬд³öÇâäåËáÓëÒÒ´¼ÔÚ¼ÓÈÈʱ·´Ó¦µÄ»¯Ñ§·½³Ìʽ      ¡£
£¨2£©ÊÔ¹ÜIÖз´Ó¦³ýÁËÉú³ÉäåÒÒÍ飬»¹¿ÉÄÜÉú³ÉµÄÓлúÎïÓР        _           ¡¢
             (д³öÁ½ÖÖÓлúÎïµÄ½á¹¹¼òʽ)¡£
£¨3£©äåÒÒÍéµÄ·Ðµã½ÏµÍ£¬Ò×»Ó·¢£¬ÎªÁËʹäåÒÒÍéÀäÄýÔÚÊԹܢòÖУ¬¼õÉÙ»Ó·¢£¬ÉÏͼÖвÉÈ¡µÄ´ëÊ©ÓР            ¡¢           _¡£
£¨4£©ÔÚ½øÐÐäåÒÒÍéÓëNaOHÒÒ´¼ÈÜÒº¹²ÈȵÄÐÔÖÊʵÑéʱ£¬°ÑÉú³ÉµÄÆøÌåͨ¹ýÏÂͼËùʾµÄ×°Öá£ÓÃÏÂͼװÖýøÐÐʵÑéµÄÄ¿µÄÊÇ     _£»ÏÂͼÖÐÓÒ±ßÊÔ¹ÜÖеÄÏÖÏóÊÇ     £»Ë®µÄ×÷ÓÃÊÇ      ¡£


¢ÅHBr + C2H5OHC2H5Br + H2O ¡¡¢ÆCH2£½CH2     CH3CH2OCH2CH3 
¢ÇÊԹܢòÈûÉÏ´øÓе¼¹ÜµÄÈû×Ó²¢ÔÚÆäÖмÓË®£»°ÑÊԹܢò·ÅÈëÊ¢ÓÐÀäË®µÄÉÕ±­ÖУ»Ê¹Ó󤵼¹ÜµÈ 
¢ÇÑéÖ¤Éú³ÉµÄÆøÌåÊÇÒÒÏ©£¨»òÑéÖ¤äåÒÒÍéÓëNaOH·¢ÉúÏûÈ¥·´Ó¦µÄ²úÎ 
¢È¸ßÃÌËá¼ØÈÜÒºµÄ×ϺìÉ«ÍÊÈ¥       ¡¡³ýÈ¥ÆøÌåÖлìÓеÄÉÙÁ¿ÒÒ´¼µÈÔÓÖÊ

½âÎöÊÔÌâ·ÖÎö£º
¢ÅÔÚ¼ÓÈȵÄÌõ¼þÏ£¬ÒÒ´¼ºÍä廯Çâ·¢ÉúÈ¡´ú·´Ó¦£¬Éú³ÉäåÒÒÍéºÍË®£¬Ôò·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇHBr + C2H5OHC2H5Br + H2O¡£
¢ÆÓÉÓÚÔÚŨÁòËáµÄ×÷ÓÃÏ£¬ÒÒ´¼Ò²¿ÉÄÜ·¢ÉúÏûÈ¥·´Ó¦Éú³ÉÒÒÏ©£¬Ò²¿ÉÄÜ·¢Éú·Ö×Ó¼äµÄÍÑË®£¬Éú³ÉÒÒÃÑ£¬Æä½á¹¹¼òʽ·Ö±ðÊÇCH2£½CH2¡¢CH3CH2OCH2CH3¡£
¢ÇÓÉÓÚäåÒÒÍéÒ×»Ó·¢£¬ÔòҪʹäåÒÒÍéÍéÀäÄýÔÚÊԹܢòÖУ¬¼õÉÙ»Ó·¢£¬ÆäÕýÈ·µÄ·½·¨ÓÐÊԹܢòÈûÉÏ´øÓе¼¹ÜµÄÈû×Ó²¢ÔÚÆäÖмÓË®£»°ÑÊԹܢò·ÅÈëÊ¢ÓÐÀäË®µÄÉÕ±­ÖУ»Ê¹Ó󤵼¹ÜµÈ¡£
¢ÈÔÚÇâÑõ»¯ÄƵĴ¼ÈÜÒºÖУ¬äåÒÒÍé·¢ÉúÏûÈ¥·´Ó¦Éú³ÉÒÒÏ©£¬ÒÒÏ©º¬ÓÐ̼̼˫¼ü£¬ÄÜʹËáÐÔ¸ßÃÌËá¼ØÈÜÒºÍÊÉ«£¬ËùÒÔ¸ù¾Ý×°ÖÃͼ¿ÉÖª£¬¸ÃʵÑéÄ¿µÄÊÇÑéÖ¤Éú³ÉµÄÆøÌåÊÇÒÒÏ©£¨»òÑéÖ¤äåÒÒÍéÓëNaOH·¢ÉúÏûÈ¥·´Ó¦µÄ²úÎ£¬¶øʵÑéÏÖÏóÊǸßÃÌËá¼ØÈÜÒºµÄ×ϺìÉ«ÍÊÈ¥¡£µ«ÓÉÓÚÒÒ´¼Ò×»Ó·¢£¬ÇÒÒÒ´¼Ò²ÄÜʹËáÐÔ¸ßÃÌËá¼ØÈÜÒºÍÊÉ«£¬ËùÒÔË®µÄ×÷ÓÃÊdzýÈ¥ÆøÌåÖлìÓеÄÉÙÁ¿ÒÒ´¼µÈÔÓÖÊ£¬·ÀÖ¹¸ÉÈÅÒÒÏ©µÄÐÔÖʼìÑé¡£
¿¼µã£º¿¼²éÒÒ´¼¡¢äåÒÒÍé¡¢ÒÒÏ©µÈÓлúÎïµÄÐÔÖÊ¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

ÌÇÀà¡¢ÓÍÖ¬¡¢µ°°×ÖÊΪ¶¯ÎïÐÔºÍÖ²ÎïÐÔʳÎïÖеĻù±¾ÓªÑøÎïÖÊ¡£
(1)µ°°×ÖÊ¡¢µí·Û¡¢Ö¬·¾ÈýÖÖÓªÑøÎïÖÊÖÐË®½âµÄ×îÖÕ²úÎïÄÜÓëÐÂÖÆCu(OH)2Ðü×ÇÒº·´Ó¦µÄÊÇ________£¬ÖÆÔì·ÊÔíµÄÖ÷ÒªÔ­ÁÏÊÇ________¡£
(2)µ°°×ÖÊË®½âµÄ×îÖÕ²úÎïÊÇ____________¡£
(3)ÏÂÁÐÓйØ˵·¨ÖÐÕýÈ·µÄÊÇ____________¡£
A£®µ°°×ÖÊÖÐÖ»º¬C¡¢H¡¢OÈýÖÖÔªËØ
B£®ÓÍÖ¬ÔÚÈËÌåÖз¢ÉúË®½âµÄ²úÎïÊÇ°±»ùËá
C£®ÌÇÀಢ²»¶¼ÓÐÌðζ
D£®ÌÇÀà¡¢ÓÍÖ¬¡¢µ°°×Öʶ¼ÄÜ·¢ÉúË®½â·´Ó¦
(4)µí·ÛÈÜÒººÍµ°°×ÖÊÈÜÒº¶¼ÊǽºÌ壬ÓÃÒ»Êø¹âͨ¹ýÆäÈÜÒº£¬¶¼²úÉú____________£¬Èô¼ìÑéËüÃÇ¿ÉÑ¡ÓõÄÊÔ¼ÁÊÇ____________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

ijÈËÉè¼Æµí·ÛÀûÓ÷½°¸ÈçÏÂͼËùʾ£º

ÆäÖУºAÊÇÒÒÏ©ÄÜ´ßÊìË®¹û£¬BÊǸ߷Ö×Ó»¯ºÏÎDÊÇÓÐË®¹ûÏãζµÄÎïÖÊ¡£Çë»Ø´ðÒÔÏÂÎÊÌ⣺
(1)¡°C6H12O6¡±µÄÃû³ÆÊÇ________£¬AµÄµç×ÓʽΪ__________£¬CÖк¬ÓйÙÄÜÍÅÃû³Æ      £»
(2) A¡úB·´Ó¦ÀàÐÍ_________________£»C¡úD·´Ó¦ÀàÐÍ_________________
(3)д³öÏÂÁÐת»¯µÄ»¯Ñ§·½³Ìʽ
¢ÙA¡úB£º                                                       £¬
¢ÚC¡úD£º                                                       £¬
¢ÛCH3CH2OH¡úCH3CHO£º                                        ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÎÊ´ðÌâ

ÒÒ´¼ÆûÓÍ×÷ΪһÖÖÐÂÐÍÇå½àȼÁÏ£¬ÊÇÄ¿Ç°ÊÀ½çÉÏ¿ÉÔÙÉúÄÜÔ´µÄ·¢Õ¹Öص㣬¶øÇÒ¾ßÓнϺõľ­¼ÃЧÒæºÍÉç»áЧÒ棬ÖÕ½«³ÉΪÆûÓͺͲñÓ͵ÄÌæ´úÆ·¡£

(1)д³öÒÒ´¼ÍêȫȼÉյĻ¯Ñ§·½³Ìʽ£º______________________________¡£
(2)ÒÒ´¼È¼ÉÕʱÈç¹ûÑõÆø²»×㣬¿ÉÄÜ»¹ÓÐCOÉú³É¡£ÓÃÈçͼװÖÃÑéÖ¤ÒÒ´¼µÄȼÉÕ²úÎïÖÐÓÐCO¡¢CO2¡¢H2O£¬Ó¦½«ÒÒ´¼µÄȼÉÕ²úÎïÒÀ´Îͨ¹ý(°´ÆøÁ÷´Ó×óµ½ÓÒµÄ˳ÐòÌî×°ÖñàºÅ)________¡£

(3)ʵÑéʱ¿É¹Û²ìµ½×°ÖâÚÖÐAÆ¿µÄʯ»ÒË®±ä»ë×Ç¡£AÆ¿ÈÜÒºµÄ×÷ÓÃÊÇ________£»BÆ¿ÈÜÒºµÄ×÷ÓÃÊÇ________£»CÆ¿ÈÜÒºµÄ×÷ÓÃÊÇ_________________________¡£
(4)×°Öâ۵Ä×÷ÓÃÊÇ________£»×°ÖâÙÖÐËùÊ¢µÄÊÇ________£¬×÷ÓÃÊÇ______________________¡£
(5)×°ÖâÜÖÐËùÊ¢µÄ¹ÌÌåÒ©Æ·ÊÇ________£¬Ëü¿ÉÒÔÑéÖ¤µÄ²úÎïÊÇ________¡£
(6)βÆøÓ¦ÈçºÎ´¦Àí£¿_________¡£
(7)º£µ×ÓдóÁ¿µÄ¼×ÍéË®ºÏÎï¡£µÈÖÊÁ¿µÄ¼×ÍéºÍÒÒ´¼ÍêȫȼÉÕ²úÉúÎÂÊÒÆøÌåCO2½Ï¶àµÄÊÇ________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÎÊ´ðÌâ

ʵÑéÊÒÖÆÈ¡ÒÒËᶡõ¥µÄʵÑé×°ÖÃÓÐÈçÓÒÏÂͼËùʾÁ½ÖÖ×°Öù©Ñ¡Óá£ÆäÓйØÎïÖʵÄÎïÀíÐÔÖÊ

ÈçÏÂ±í£º

 
ÒÒËá
1-¶¡´¼
ÒÒËᶡõ¥
ÈÛµã(¡æ)
16.6
£­89.5
£­73.5
·Ðµã(¡æ)
117.9
117
126.3
ÃܶÈ(g/cm3)
1.05
0.81
0.88
Ë®ÈÜÐÔ
»¥ÈÜ
¿ÉÈÜ(9g/100gË®)
΢ÈÜ
£¨1£©ÖÆÈ¡ÒÒËᶡõ¥µÄ×°ÖÃӦѡÓÃ_______(Ìî¡°¼×¡±»ò¡°ÒÒ¡±)¡£²»Ñ¡ÁíÒ»ÖÖ×°ÖõÄÀíÓÉÊÇ                     ¡£
£¨2£©¸ÃʵÑéÉú³ÉÎïÖгýÁËÖ÷²úÎïÒÒËᶡõ¥Í⣬»¹¿ÉÄÜÉú³ÉµÄÓлú¸±²úÎïÓУ¨Ð´³ö½á¹¹¼òʽ£©£º                       ¡¢                   ¡£
£¨3£©õ¥»¯·´Ó¦ÊÇÒ»¸ö¿ÉÄæ·´Ó¦£¬ÎªÌá¸ß1-¶¡´¼µÄÀûÓÃÂÊ£¬¿É²ÉÈ¡µÄ´ëÊ©ÊÇ     ¡£
£¨4£©´ÓÖƱ¸ÒÒËᶡõ¥ËùµÃµÄ»ìºÏÎïÖзÖÀë¡¢Ìá´¿ÒÒËᶡõ¥Ê±£¬ÐèÒª¾­¹ý¶à²½²Ù×÷£¬ÏÂÁÐͼʾµÄ²Ù×÷ÖУ¬¿Ï¶¨ÐèÒªµÄ»¯Ñ§²Ù×÷ÊÇ___________£¨Ñ¡Ìî´ð°¸±àºÅ£©¡£
£¨5£©ÓлúÎïµÄ·ÖÀë²Ù×÷ÖУ¬¾­³£ÐèҪʹÓ÷ÖҺ©¶·µÈÒÇÆ÷¡£Ê¹Ó÷ÖҺ©¶·Ç°±ØÐë   £»Ä³Í¬Ñ§ÔÚ½øÐзÖÒº²Ù×÷ʱ£¬Èô·¢ÏÖÒºÌåÁ÷²»ÏÂÀ´£¬Æä¿ÉÄÜÔ­Òò³ý·ÖҺ©¶·»îÈû¶ÂÈûÍ⣬»¹¿ÉÄÜ                      ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÊµÑéÌâ

£¨10·Ö£©Ä³»¯Ñ§»î¶¯Ð¡×éÉè¼ÆÒÔÏÂ×°ÖýøÐв»Í¬µÄʵÑé¡£ÆäÖÐaΪÓÃÓÚ¹ÄÈë¿ÕÆøµÄÆøÄÒ£¬bΪÂÝÐý×´Í­Ë¿£¬cÖÐÊ¢ÓбùË®¡£

£¨1£©ÈôÓÃA×°ÖÃ×öÒÒ´¼ÓëÒÒËáµÄõ¥»¯·´Ó¦ÊµÑ飬Ôò»¹ÐèÁ¬½ÓµÄ×°ÖÃÊÇ      £¨ÌîÐòºÅ£©£¬¸Ã×°ÖÃÖÐÓ¦¼ÓÈëÊÔ¼Á         ¡£´ÓʵÑ鰲ȫ½Ç¶È¿¼ÂÇ£¬A×°ÖÃÊÔ¹ÜÖгý¼ÓÈë·´Ó¦ÒºÍ⣬»¹Ðè¼ÓÈëµÄ¹ÌÌåÎïÖÊÊÇ         ¡£AÖз´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º                    ¡£
£¨2£©¸ÃС×éͬѧÓû×öÒÒ´¼Ñõ»¯³ÉÒÒÈ©µÄʵÑé²¢ÊÕ¼¯Éú³ÉµÄ²úÎÔòӦѡÓõÄ×°ÖÃÊÇ        £¨ÌîÐòºÅ£©£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ______________________________________                 ¡£
£¨3£©ÈôÔÙÓÃÖƵõÄÒÒÈ©ÈÜÒº½øÐÐÒø¾µ·´Ó¦£¬Ñ¡ÓÃ2%µÄAgNO3ÈÜÒººÍ2%µÄÏ¡°±Ë®ÅäÖÆÒø°±ÈÜÒºµÄ²Ù×÷ÊÇ                                                                   ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÊµÑéÌâ

£¨ 11·Ö£©ÒÒ´¼µÄ·ÐµãÊÇ78¡æ£¬ÄÜÓëË®ÒÔÈÎÒâ±È»ìÈÜ¡£ÒÒÃѵķеãΪ34.6¡æ£¬ÄÑÈÜÓÚË®£¬ÔÚ±¥ºÍNa2CO3ÈÜÒºÖм¸ºõ²»ÈÜ£¬ÒÒÃѼ«Ò×ȼÉÕ¡£ÊµÑéÊÒÖÆÃѵķ´Ó¦Ô­ÀíÊÇ£º
2CH3CH2OHH2O + CH3CH2¡ªO¡ªCH2CH3 (ÒÒÃÑ)

£¨1£©¼×ͼºÍÒÒͼÊÇÁ½Ì×ʵÑéÊÒÖÆÒÒÃѵÄ×°Öã¬Ñ¡×°ÖÃ___(Ìî¡°¼×¡±»ò¡°ÒÒ¡±)×îºÏÀí£¬ÀíÓÉÊÇ_  ¡£
£¨2£©·´Ó¦ÒºÖÐÓ¦¼ÓÈë·Ðʯ£¬Æä×÷ÓÃÊÇ____________¡£
£¨3£©·´Ó¦ÖÐζȼƵÄÕýȷλÖÃÊÇË®ÒøÇòÖÃÓÚ________________________¡£
£¨4£©ÓÃÉÏÊö×°ÖÃÒÒÖƵõÄÒÒÃÑÖпÉÄܺ¬ÓдóÁ¿µÄÔÓÖÊ£¬¸ÃÔÓÖÊÊÇ__________£¬³ýÈ¥ÕâÖÖÔÓÖʵļòÒ×·½·¨ÊÇ________________________________¡£
£¨5£©Èç¹ûζÈÌ«¸ß£¨Èç170¡æ£©£¬½«»á·¢ÉúÒ»¸öÓлú¸±·´Ó¦£¬·´Ó¦·½³ÌʽΪ£º__________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÊµÑéÌâ

ΪÁ˲ⶨÒÒ´¼µÄ½á¹¹Ê½ÊÇ
£¬ÀûÓÃÒÒ´¼ºÍÄƵķ´Ó¦£¬Éè¼ÆÈçͼװÖýøÐÐʵÑ飬ÔÚÉÕÆ¿ÖзÅÈë×ãÁ¿µÄÄÆ£¬´Ó·ÖҺ©¶·Öлº»ºµÎÈëÒ»¶¨Á¿µÄÒÒ´¼£¬Í¨¹ý²âÁ¿Á¿Í²ÖÐË®µÄÌå»ý£¬¾Í¿ÉÖª·´Ó¦Éú³ÉµÄÇâÆøµÄÌå»ý¡£

£¨1£©ÊµÑéÇ°¼ìÑé¸Ã×°ÖõÄÆøÃÜÐÔµÄʵÑé²Ù×÷ÊÇ
__________________________________________________¡£
£¨2£©ÓÐÈËÈÏΪװÖÃÖÐÓпÕÆø£¬Ëù²âµÄÆøÌåÌå»ýÓ¦¿Û³ý×°ÖÃÖпÕÆøµÄÌå»ý£¬²ÅÊÇÇâÆøµÄÌå»ý£¬ÄãÈÏΪ________£¨Ìî¡°ÕýÈ·¡±»ò¡°²»ÕýÈ·¡±£©¡£
£¨3£©Èç¹ûʵÑ鿪ʼǰbµ¼¹ÜÄÚδ³äÂúË®£¬ÔòʵÑé½á¹û½«________£¨Ìî¡°Æ«´ó¡±»ò¡°Æ«Ð¡¡±£©¡£
£¨4£©Èô²âµÃÓÐ1.15 g C2H6O²Î¼Ó·´Ó¦£¬°ÑÁ¿Í²cÖеÄË®µÄÌå»ý»»Ëã³É±ê×¼×´¿öÏÂH2µÄÌå»ýΪ280 mL£¬ÊÔ½áºÏ¼ÆËãºÍÌÖÂÛ£¬ÅжÏÏÂÃ棨¢ñ£©ºÍ£¨¢ò£©Á½Ê½ÖУ¬ÄĸöÕýÈ·________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÏÂÁз´Ó¦ÖУ¬ÊôÓڼӳɷ´Ó¦µÄÊÇ

A£®¼×ÍéÓëÂÈÆø·´Ó¦ÖÆÈ¡Ò»Âȼ×Íé B£®ÒÒËáÓëÒÒ´¼·´Ó¦ÖÆÈ¡ÒÒËáÒÒõ¥
C£®±½·ÓÓë±¥ºÍäåË®·´Ó¦Éú³ÉÈýäå±½·Ó D£®ÒÒÏ©ÓëÂÈ»¯Çâ·´Ó¦ÖÆÈ¡ÂÈÒÒÍé

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸