Question

ÈçͼËùʾ£¬µ±¹Ø±ÕKʱ£¬ÏòAÖгäÈë2molX¡¢7molY£¬ÏòBÖгäÈë4molX¡¢14molY£¬ÆðʼʱV_£¨A£©=V_£¨B£©=mL£¬ÔÚÏàͬζȺÍÓд߻¯¼Á´æÔÚµÄÌõ¼þÏ£¬Á½ÈÝÆ÷¸÷×Ô·¢ÉúÏÂÁз´Ó¦£º2X£¨g£©+2Y£¨g£©?Z£¨g£©+2W£¨g£©¡÷H£¼0´ïµ½Æ½ºâ£¨¢ñ£©Ê±V_£¨B£©=0.9mL£¬ÊԻشð£º

£¨1£©BÖÐXµÄת»¯ÂʦÁ£¨X£©_BΪ

 

£®
£¨2£©AÖÐWºÍBÖÐZµÄÎïÖʵÄÁ¿µÄ±È½Ï£ºn£¨W£©_A

 

 n£¨Z£©_B £¨Ì¡¢£¾¡¢»ò=£©
£¨3£©´ò¿ªK£¬¹ýÒ»¶Îʱ¼äÖØдïƽºâ£¨¢ò£©Ê±£¬BµÄÌå»ýΪ

 

Éý£¨Óú¬mµÄ´úÊýʽ±íʾ£¬Á¬Í¨¹ÜÖÐÆøÌåÌå»ý²»¼Æ£©
£¨4£©ÒªÊ¹BÈÝÆ÷»Ö¸´Ô­À´·´Ó¦Ç°µÄÌå»ý£¬¿É²ÉÈ¡µÄ´ëÊ©ÊÇ

 

£¨Ñ¡Ì
a£®Éý¸ßζȠ b£®½µµÍζȠc£®³äÈëÏ¡ÓÐÆøÌ壮

Answer 1

¿¼µã£º»¯Ñ§Æ½ºâµÄ¼ÆËã,»¯Ñ§Æ½ºâµÄÓ°ÏìÒòËØ

רÌ⣺

·ÖÎö£º£¨1£©¸ù¾ÝÃܶȱ仯¼ÆËãƽºâʱBµÄÌå»ý£¬ÀûÓÃÆøÌåµÄÌå»ýÖ®±ÈµÈÓÚÎïÖʵÄÁ¿Ö®±È¼ÆËãƽºâºóBÖÐÆøÌåµÄÎïÖʵÄÁ¿£¬ÔÙÀûÓòîÁ¿·¨¼ÆËãBÖвμӷ´Ó¦XµÄÎïÖʵÄÁ¿£¬½ø¶ø¼ÆËãת»¯ÂÊ£»
£¨2£©AΪºãκãÈÝ£¬BΪºãκãѹ£¬Õý·´Ó¦ÎªÆøÌåÎïÖʵÄÁ¿¼õСµÄ·´Ó¦£¬AÖÐѹǿ¼õС£¬AÖÐËùµ½´ïµÄƽºâµÈЧΪÔÚBµÄƽºâ»ù´¡ÉϽµµÍѹǿ£¬ÔÙ½áºÏA¡¢BÖÐXµÄת»¯ÂÊ´óС½øÐнâ´ð£»
£¨3£©´ò¿ªK£¬ÎªºãκãѹÌõ¼þÏ£¬¹ýÒ»¶Îʱ¼äÖØдïƽºâ£¨¢ò£©ÓëÔ­BÈÝÆ÷µÄƽºâΪµÈЧƽºâ£¬XµÄת»¯ÂÊÏàͬ£¬¼ÆËãƽºâʱ·´Ó¦»ìºÏÎïµÄ×ÜÎïÖʵÄÁ¿£¬ÀûÓÃÆøÌåµÄÌå»ýÖ®±ÈµÈÓÚÎïÖʵÄÁ¿Ö®±È¼ÆËã×ÜÌå»ý£¬½ø¶ø¼ÆËãBµÄÌå»ý£»
£¨4£©ÒÀ¾Ý»¯Ñ§·´Ó¦ÊÇÆøÌåÌå»ý¼õСµÄ·ÅÈÈ·´Ó¦£¬½áºÏÓ°Ï컯ѧƽºâÓ°ÏìÒòËغÍƽºâÒƶ¯Ô­Àí·ÖÎö£®

½â´ð£º ½â£º£¨1£©´ïµ½Æ½ºâ£¨¢ñ£©Ê±£¬BÖÐÃܶȱäΪԭÀ´µÄ

10

9

£¬»ìºÏÆøÌå×ÜÖÊÁ¿ÏàµÈ£¬ÔòBµÄÌå»ýΪ0.9aL£¬ÆøÌåµÄÌå»ýÖ®±ÈµÈÓÚÎïÖʵÄÁ¿Ö®±È£¬¹ÊƽºâºóBÖÐÆøÌåµÄÎïÖʵÄÁ¿=£¨2mol+7mol£©¡Á

0.9aL

aL

=8.1mol£¬Ôò£º
2X£¨g£©+2Y£¨g£©?Z£¨g£©+2W£¨g£© ÎïÖʵÄÁ¿¼õС
2               1
1.8mol £¨2mol+7mol£©-8.1mol=0.9mol
¹ÊBÖÐXµÄת»¯ÂÊ=

1.8mol

2mol

¡Á100%=90%£¬
¹Ê´ð°¸Îª£º90%£»
£¨2£©AΪºãκãÈÝ£¬BΪºãκãѹ£¬Õý·´Ó¦ÎªÆøÌåÎïÖʵÄÁ¿¼õСµÄ·´Ó¦£¬AÖÐѹǿ¼õС£¬AÖÐËùµ½´ïµÄƽºâµÈЧΪÔÚBµÄƽºâ»ù´¡ÉϽµµÍѹǿ£¬BÖеÄƽºâÏòÄæ·´Ó¦·½ÏòÒƶ¯µ½´ïAÖеÄƽºâ£¬¹ÊAÖÐת»¯ÂʽÏС£¬AÖÐXµÄÁ¿ÎªBÖеÄ2±¶£¬WµÄ»¯Ñ§¼ÆÁ¿ÊÇZµÄ2±¶£¬Ôòn£¨Z£©_A£¼n£¨W£©_B£¬¹Ê´ð°¸Îª£º£¼£»
£¨3£©´ò¿ªK£¬ÎªºãκãѹÌõ¼þÏ£¬¹ýÒ»¶Îʱ¼äÖØдïƽºâ£¨¢ò£©ÓëÔ­BÈÝÆ÷µÄƽºâΪµÈЧƽºâ£¬XµÄת»¯ÂÊÏàͬ£¬Ôò²Î¼Ó·´Ó¦µÄXµÄÎïÖʵÄÁ¿=£¨4mol+2mol£©¡Á90%=5.4mol£¬Ôò£º
2X£¨g£©+2Y£¨g£©?Z£¨g£©+2W£¨g£© ÎïÖʵÄÁ¿¼õС
2               1
5.4mol         2.7mol
¹Êƽºâʱ·´Ó¦»ìºÏÎïµÄ×ÜÎïÖʵÄÁ¿=4mol+14mol+2mol+7mol-2.7mol=24.3mol£¬Ìå»ýÖ®±ÈµÈÓÚÎïÖʵÄÁ¿Ö®±È£¬¹Êƽºâºó×ÜÌå»ý=mL¡Á

24.3

14+4

=1.35mL£¬ÔòBµÄÌå»ýΪ1.35mL-mL=0.35m L£¬
¹Ê´ð°¸Îª£º0.35m£»
£¨4£©a£®·´Ó¦ÊÇ·ÅÈÈ·´Ó¦£¬Éý¸ßζÈƽºâÄæÏò½øÐУ¬ÆøÌåÌå»ýÔö´ó£¬¿ÉÒÔ»Ö¸´Ô­À´Ìå»ý£¬¹ÊaÕýÈ·£»
b£®·´Ó¦ÊÇ·ÅÈÈ·´Ó¦£¬½µµÍζÈƽºâÕýÏò½øÐУ¬ÆøÌåÌå»ý¼õС£¬²»¿ÉÒÔ»Ö¸´Ô­À´Ìå»ý£¬¹Êb´íÎó£»
c£®³äÈëÏ¡ÓÐÆøÌ壬ѹǿ¼õС£¬Æ½ºâÄæÏò½øÐУ¬ÆøÌåÌå»ýÔö´ó£¬¿ÉÒÔ»Ö¸´Ô­À´Ìå»ý£¬¹ÊcÕýÈ·£»
¹Ê´ð°¸Îª£ºac£®

µãÆÀ£º±¾Ì⿼²éÁË»¯Ñ§Æ½ºâÓ°ÏìÒòËØ£¬Æ½ºâ¼ÆËã·ÖÎö£¬µÈЧƽºâÀí½âÓ¦Óã¬ÕÆÎÕ»ù´¡Êǹؼü£¬ÌâÄ¿ÄѶÈÖеȣ®