·ÖÎö £¨1£©ÔËÓÃÊýѧ¹éÄÉ·¨Ö¤Ã÷£¬Ê×ÏÈÑéÖ¤n=2µÄÇé¿ö£¬¼ÙÉèn=k£¬½áÂÛ³ÉÁ¢£¬ÔÙÓɺ¯Êýy=ax+$\frac{b}{x}$µÄÐÔÖÊ£¬¿ÉÖ¤n=k+1Ò²³ÉÁ¢£»
£¨2£©ÔËÓÃÊýѧ¹éÄÉ·¨Ö¤Ã÷£¬Ê×ÏÈÑéÖ¤n=2µÄÇé¿ö£¬¼ÙÉèn=k£¬½áÂÛ³ÉÁ¢£¬ÔÙ½áºÏÌõ¼þ£¬»¯¼òÕûÀí£¬¼´¿ÉµÃµ½n=k+1Ò²³ÉÁ¢£¬½ø¶øµÃÖ¤£®
½â´ð Ö¤Ã÷£º£¨1£©µ±n=2ʱ£¬a2=$\frac{1}{2}$+1=$\frac{3}{2}$£¾$\sqrt{2}$£¬³ÉÁ¢£»
¼ÙÉèn=kʱ£¬ak£¾$\sqrt{2}$³ÉÁ¢£»
µ±n=k+1ʱ£¬ak+1=$\frac{1}{2}$ak+$\frac{1}{{a}_{k}}$£¾$\frac{1}{2}$•$\sqrt{2}$+$\frac{1}{\sqrt{2}}$=$\sqrt{2}$£¬
Ôòn=k+1ʱ£¬Ò²³ÉÁ¢£®
¶ÔÒ»ÇÐn¡ÊN*£¬n¡Ý2£¬an£¾$\sqrt{2}$£®
£¨2£©µ±n=2ʱ£¬b2=$\frac{2}{\sqrt{{{a}_{2}}^{2}-2}}$=$\frac{2}{\sqrt{\frac{9}{4}-2}}$=4£¬
c2=$\frac{4{a}_{2}}{{{a}_{2}}^{2}-2}$=$\frac{4¡Á\frac{3}{2}}{\frac{9}{4}-2}$=24£¬b2Óëc2¶¼ÊÇÕýÕûÊý£»
¼ÙÉèn=k£¬bkÓëck¶¼ÊÇÕýÕûÊý£¬
¼´ÓÐn=k+1ʱ£¬bk+1=$\frac{2}{\sqrt{{{a}_{k+1}}^{2}-2}}$=$\frac{2}{\sqrt{£¨\frac{1}{2}{a}_{k}+\frac{1}{{a}_{k}}£©^{2}-2}}$=$\frac{2}{\frac{1}{2}{a}_{k}-\frac{1}{{a}_{k}}}$
=$\frac{4{a}_{k}}{{{a}_{k}}^{2}-2}$=ckΪÕýÕûÊý£¬
ck+1=$\frac{4{a}_{k+1}}{{{a}_{k+1}}^{2}-2}$=$\frac{8{a}_{k}£¨{{a}_{k}}^{2}+2£©}{£¨{{a}_{k}}^{2}-2£©^{2}}$=$\frac{4{a}_{k}}{{{a}_{k}}^{2}-2}$•$\frac{2£¨{{a}_{k}}^{2}+2£©}{{{a}_{k}}^{2}-2}$
=ck•2£¨1+$\frac{4}{{{a}_{k}}^{2}-2}$£©=ck•2£¨1+bk2£©£¬¼´ÎªÕýÕûÊý£®
ÔòÓжÔÒ»ÇÐn¡ÊN*£¬n¡Ý2£¬bnÓëcn¶¼ÊÇÕýÕûÊý£®
µãÆÀ ±¾Ì⿼²éÊýѧ¹éÄÉ·¨µÄÔËÓã¬Í¬Ê±¿¼²é²»µÈʽµÄÐÔÖʺͻ¯¼òÕûÀíµÄÔËËãÄÜÁ¦£¬ÊôÓÚÖеµÌ⣮
| Äê¼¶ | ¸ßÖÐ¿Î³Ì | Äê¼¶ | ³õÖÐ¿Î³Ì |
| ¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
| ¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
| ¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
¿ÆÄ¿£º¸ßÖÐÊýѧ À´Ô´£º ÌâÐÍ£º½â´ðÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÊýѧ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÊýѧ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÊýѧ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÊýѧ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÊýѧ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
| A£® | $\frac{9}{16}$ | B£® | $\frac{3}{8}$ | C£® | $\frac{18}{25}$ | D£® | $\frac{12}{25}$ |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÊýѧ À´Ô´£º ÌâÐÍ£º½â´ðÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÊýѧ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
| A£® | ¶Û½ÇÈý½ÇÐÎ | B£® | Èñ½ÇÈý½ÇÐÎ | C£® | Ö±½ÇÈý½ÇÐÎ | D£® | ÐÎ×´²»ÄÜÈ·¶¨ |
²é¿´´ð°¸ºÍ½âÎö>>
¹ú¼ÊѧУÓÅÑ¡ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com