·ÖÎö £¨1£©¸ù¾ÝʵÑéµÄÔÀíÈ·¶¨ËùÐèµÄ²âÁ¿µÄÎïÀíÁ¿£¬´Ó¶øÈ·¶¨²»ÐèÒªµÄÆ÷²Ä£»
£¨2£©¸ù¾ÝʵÑéµÄÔÀíÒÔ¼°²Ù×÷ÖеÄ×¢ÒâÊÂÏîÈ·¶¨ÕýÈ·µÄ²Ù×÷²½Ö裻
£¨3£©¸ù¾ÝÊúÖ±·½ÏòÉÏÁ¬ÐøÏàµÈʱ¼äÄÚµÄÎ»ÒÆÖ®²îÊÇÒ»ºãÁ¿Çó³öÏàµÈµÄʱ¼ä¼ä¸ô£¬½áºÏË®Æ½Î»ÒÆºÍʱ¼ä¼ä¸ôÇó³ö³õËÙ¶È£®¸ù¾Ýij¶Îʱ¼äÄ򵀮½¾ùËٶȵÈÓÚÖмäʱ¿ÌµÄ˲ʱËÙ¶ÈÇó³öºá×ø±êΪ10cmµãµÄÊúÖ±·ÖËÙ¶È£¬½áºÏËÙ¶Èʱ¼ä¹«Ê½Çó³öÅ׳öµãµ½´ï¸ÃµãµÄʱ¼ä£¬½áºÏÔ˶¯Ñ§¹«Ê½Çó³öÅ׳öµãµ½´ï¸ÃµãµÄÊúÖ±Î»ÒÆºÍË®Æ½Î»ÒÆ£¬´Ó¶øµÃ³öÅ׳öµãµÄ×ø±ê£®
½â´ð ½â£º£¨1£©ÊµÑéÖÐÆ½Å×Ô˶¯µÄʱ¼äÓÉÊúÖ±·½ÏòÉϵĸ߶ÈÇó³ö£¬²»ÐèÒªÃë±í²âÁ¿£¬¹ÊF²»ÐèÒª£®
£¨2£©A¡¢ÎªÁ˱£Ö¤Ð¡ÇòµÄ³õËÙ¶Èˮƽ£¬Ð±²ÛµÄÄ©¶ËÐèˮƽ£¬¹ÊAÕýÈ·£®
B¡¢Îª¼õСʵÑéÎó²î£¬Ó¦Ê¹Ð¡Çòÿ´Î´Óб²Û¹ìµÀÉÏͬһλÖùöÏ£¬¹ÊB´íÎó£®
C¡¢¸ÃʵÑé²»ÐèҪƽºâĦ²ÁÁ¦£¬Ö»ÒªÈÃСÇòÿ´Î´Óб²ÛµÄͬһλÖÃÓɾ²Ö¹¹öÏ£¬±£Ö¤Æ½Å×Ô˶¯µÄ³õËÙ¶ÈÏàµÈ¼´¿É£¬¹ÊC´íÎó£¬DÕýÈ·£®
¹ÊÑ¡£ºAD£®
£¨3£©ÔÚÊúÖ±·½ÏòÉÏ£¬¸ù¾Ý¡÷y=gT2µÃÏàµÈµÄʱ¼ä¼ä¸ôΪ£ºT=$\sqrt{\frac{¡÷y}{g}}=\sqrt{\frac{0.2-0.1}{10}}s=0.1s$£¬
ÔòƽÅ×Ô˶¯µÄ³õËÙ¶ÈΪ£º${v}_{0}=\frac{x}{T}=\frac{0.1}{0.1}m/s=1m/s$£®
x=10cm´¦µãµÄÊúÖ±·ÖËÙ¶ÈΪ£º${v}_{y}=\frac{0.3}{0.2}m/s=1.5m/s$£¬
ÔòÅ׳öµãµ½¸ÃµãµÄʱ¼äΪ£º$t=\frac{{v}_{y}}{g}=\frac{1.5}{10}s=0.15s$£¬
Å׳öµãµ½¸ÃµãµÄË®Æ½Î»ÒÆÎª£º¡÷x=v0t=1¡Á0.15m=0.15m=15cm£¬
ÊúÖ±Î»ÒÆÎª£º$¡÷y=\frac{1}{2}g{t}^{2}=\frac{1}{2}¡Á10¡Á0.1{5}^{2}$m=0.1125m=11.25cm£¬
ÔòÅ׳öµãµÄºá×ø±êΪ£ºx=10-15cm=-5cm£¬×Ý×ø±êΪ£ºy=10-11.25cm=-1.25cm£®
¹Ê´ð°¸Îª£º£¨1£©F£»£¨2£©AD£»£¨3£©1£¬£¨-5cm£¬-1.25cm£©
µãÆÀ ½â¾ö±¾ÌâµÄ¹Ø¼üÖªµÀʵÑéµÄÔÀíÒÔ¼°²Ù×÷ÖеÄ×¢ÒâÊÂÏ֪µÀƽÅ×Ô˶¯ÔÚˮƽ·½ÏòºÍÊúÖ±·½ÏòÉϵÄÔ˶¯¹æÂÉ£¬½áºÏÔ˶¯Ñ§¹«Ê½ºÍÍÆÂÛÁé»îÇó½â£¬ÄѶȲ»´ó£®
| Äê¼¶ | ¸ßÖÐ¿Î³Ì | Äê¼¶ | ³õÖÐ¿Î³Ì |
| ¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
| ¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
| ¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º½â´ðÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÊµÑéÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
| A£® | Ñо¿´Ó¹ãÖÝ¿ªÍù±±¾©µÄÒ»Áл𳵵ÄÔËÐÐËÙ¶È | |
| B£® | Ñо¿ÉñÖ󮧼ÅÓîÖæ·É´¬ÈƵØÇò·ÉÐеÄÖÜÆÚ | |
| C£® | ½ÌÁ·Ô±Ñо¿°ÙÃ×ÈüÅÜÔ˶¯Ô±µÄÆðÅܶ¯×÷ | |
| D£® | Ñо¿µØÇòÈÆÌ«Ñô¹«×ªµÄ¹ì¼£ |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º½â´ðÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÊµÑéÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
| A£® | ½öµ±A¡¢BÓëÆ½°å³µÉϱíÃæ¼äµÄ¶¯Ä¦²ÁÒòËØÖ®±ÈΪ¦ÌA£º¦ÌB=2£º3ʱ£¬A¡¢B¡¢C×é³ÉϵͳµÄ¶¯Á¿²ÅÊØºã | |
| B£® | ÎÞÂÛA¡¢BÓëÆ½°å³µÉϱíÃæ¼äµÄ¶¯Ä¦²ÁÒòËØÊÇ·ñÏàͬ£¬A¡¢B¡¢C×é³ÉϵͳµÄ¶¯Á¿¶¼Êغã | |
| C£® | ÒòΪF1¡¢F2µÈ´ó·´Ïò£¬¹ÊA¡¢B×é³ÉµÄϵͳµÄ»úеÄÜÊØºã | |
| D£® | ÈôA¡¢BÓëС³µCÉϱíÃæ¼äµÄ¶¯Ä¦²ÁÒòËØÏàͬ£¬ÔòCÓëBµÄÔ˶¯·½ÏòÏàͬ |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
| A£® | ÒòF1=F2£¬ËùÒÔA¡¢BºÍµ¯»É×é³ÉµÄϵͳ»úеÄÜÊØºã | |
| B£® | ÒòF1=F2£¬ËùÒÔA¡¢BºÍµ¯»É×é³ÉµÄϵͳ¶¯Á¿Êغã | |
| C£® | ÓÉÓÚF1¡¢F2´óС²»±ä£¬ËùÒÔm£¬M¸÷×ÔÒ»Ö±×öÔȼÓËÙÔ˶¯ | |
| D£® | µ¯»ÉµÚÒ»´Î×ʱ£¬AºÍB×ܶ¯ÄÜ×î´ó |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
| A£® | B£® | C£® | D£® |
²é¿´´ð°¸ºÍ½âÎö>>
¹ú¼ÊѧУÓÅÑ¡ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com