·ÖÎö £¨1£©Îï¿éÀ뿪Aµãºó×öƽÅ×Ô˶¯£¬µ½´ïBµãÊ±ÑØBµãµÄÇÐÏß·½Ïò£¬¸ù¾ÝƽÅ×Ô˶¯µÄ¹æÂɵóöÎïÌåÔÚBµãµÄËÙ¶È£®
£¨2£©ÓÉ»úеÄÜÊØºã¿ÉÇóµÃÎï¿éÔÚCµãµÄËÙ¶È£»ÓÉÏòÐÄÁ¦¹«Ê½¿ÉÇóµÃÎï¿éÔÚCµãÊܵ½µÄÖ§³ÖÁ¦£®
£¨3£©Óɶ¯Á¿Êغ㶨ÂÉÇó³öÎï¿ém0ÓëÎïÌåmÅöײºó¹²Í¬ËÙ¶È£®ÒªÊ¹Îï¿é²»»¬Àëľ°å£¬Á½ÎïÌå×îºóÓ¦´ïµ½ÏàͬËٶȲ¢ÇҸպõ½´ïľ°åµÄ×îÓÒ¶Ë£¬Óɶ¯Á¿Êغ㶨ÂÉÇó³ö¹²Í¬ËÙ¶È£¬ÓÉÄÜÁ¿Êغ㶨ÂÉÇóµÃľ°åµÄ×îС³¤¶È£®
½â´ð ½â£º£¨1£©ÉèÎïÌå¾¹ýBµãµÄËÙ¶ÈΪvB£¬ÔòÓÉÆ½Å×¹æÂɿɵãº
vBsin30¡ã=v0¡¢Ù
½âµÃ£ºvB=4m/s ¡¢Ú
£¨2£©ÉèÎïÌå¾¹ýCµãµÄËÙ¶ÈΪvC£¬ÓÉ»úеÄÜÊØºãµÃ£º
$\frac{1}{2}{m_0}v_B^2+{m_0}gR£¨1+sin30¡ã£©=\frac{1}{2}{m_0}v{\;}_C^2$ ¡¢Û
¸ù¾ÝÅ£¶ÙµÚ¶þ¶¨Âɵãº
${F_N}-{m_0}g=\frac{{{m_0}v_C^2}}{R}$¡¢Ü
½âµÃ£º${F_N}=\frac{28}{3}N¡Ö9.33N$¡¢Ý
£¨3£©ÉèÁ½Îï¿éÅöײǰ£¬m0µÄËÙ¶ÈΪv1£¬Õ³ÔÚÒ»ÆðµÄËÙ¶ÈΪv2£¬Îï¿ém0ÔÚÓÚÅöײǰ£¬Óɶ¯Äܶ¨ÀíµÃ£º
$-¦Ì{m_0}g\frac{L}{2}=\frac{1}{2}{m_0}v_1^2-\frac{1}{2}{m_0}v_C^2$¡¢Þ
·¢ÉúÅöײʱ£¬Óɶ¯Á¿Êغ㶨ÂÉÓУºm0v1=£¨m0+m£©v2¡¢ß
Á½Îï¿éÓëÄ£°åÏà¶Ô»¬¶¯ÖÁ¹²ËÙv3£¬È¡ÏòÓÒΪÕý·½Ïò£¬Óɶ¯Á¿Êغ㶨Âɵãº
£¨m0+m£©v2=£¨m0+m+M£©v3¡¢à
ÓÉÄÜÁ¿ÊغãµÃ£º$¦Ì£¨{m_0}+m£©g\frac{L}{2}=\frac{1}{2}£¨{m_0}+m£©v{\;}_2^2-\frac{1}{2}£¨{m_0}+m+M£©v_3^2$¡¢á
ÁªÁ¢½âµÃ£ºL=$\frac{75}{23}$m¡Ö3.26m
ËùÒÔľ°å³¤¶È´óÓÚµÈÓÚ3.26mʱ²ÅÄܱ£Ö¤Îï¿é²»»¬Àëľ°å£®
´ð£º£¨1£©ÎïÌåµ½´ïBµãʱµÄËÙ¶È´óСvBÊÇ4m/s£®
£¨2£©Îï¿é¾¹ýCµãʱÓë¹ìµÀ¼äµ¯Á¦µÄ´óСÊÇ9.33N£®
£¨3£©Ä¾°å³¤¶È´óÓÚµÈÓÚ3.26mʱ²ÅÄܱ£Ö¤Îï¿é²»»¬Àëľ°å£®
µãÆÀ ±¾Ì⽫ƽÅס¢Ô²ÖÜÔ˶¯¼°Ö±ÏßÔ˶¯½áºÏÔÚÒ»Æð£¬Òª×¢Òâ·ÖÎöÔ˶¯¹ý³Ì£¬°ÑÎÕÿ¸ö¹ý³ÌµÄÎïÀí¹æÂÉ£®ÒªÖªµÀÎï¿éÔÚľ°åÉÏ»¬ÐÐʱ£¬Ä¦²Á²úÉúµÄÄÚÄÜÓëÏà¶ÔÎ»ÒÆÓйأ®
| Äê¼¶ | ¸ßÖÐ¿Î³Ì | Äê¼¶ | ³õÖÐ¿Î³Ì |
| ¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
| ¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
| ¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
| A£® | ³äµçµçÁ÷ԼΪ33A | |
| B£® | ÔÈËÙÐÐÊ»¾àÀë¿É´ï432km | |
| C£® | ÔÈËÙÐÐʻʱÿÃëÖÓÏûºÄµçÄÜ1.5¡Á104J | |
| D£® | ÔÈËÙÐÐʻʱËùÊÜ×èÁ¦Îª500N |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º¼ÆËãÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º¼ÆËãÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º¶àÑ¡Ìâ
| A£® | »úе²¨²¨Ô´ÔÚ¾ùÔȽéÖÊÖÐÎÞÂÛÔ˶¯Óë²»Ô˶¯£¬²¨ÔÚ½éÖÊÖеĴ«²¥ËٶȾù²»±ä | |
| B£® | ÀûÓõ¥°Ú²âÖØÁ¦¼ÓËÙ¶ÈʵÑéÖУ¬Ð¡ÇòµÄÖÊÁ¿²»ÐèÒª²âÁ¿ | |
| C£® | ºìÍâÏßÊDz»¿É¼û¹â£¬Òò´ËºìÍâÏß´ÓÒ»ÖÖ½éÖʽøÈëÁíÒ»ÖÖ½éÖÊʱ²»×ñÑÕÛÉ䶨ÂÉ | |
| D£® | ¼¤¹âÊǵ¥É«¹â£¬Ö»Óе¥É«¹â²ÅÄܲúÉú¹âµÄ¸ÉÉæÏÖÏó |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º¼ÆËãÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º¶àÑ¡Ìâ
| A£® | ÆÂµÀAB¶Ô»¬³µµÄ×÷ÓÃÁ¦ÑØÆÂÃæÏòÏ | |
| B£® | ÆÂµÀBC¶Ô»¬³µµÄ×÷ÓÃÁ¦ÎªÁã | |
| C£® | ÆÂµÀBC¶Ô»¬³µ×÷ÓÃÁ¦ÊúÖ±ÏòÉÏ | |
| D£® | ÆÂµÀCD¶Ô»¬³µµÄ×÷ÓÃÁ¦²»¿ÉÄÜ´¹Ö±ÆÂµÀÐ±ÃæÏòÉÏ |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
| A£® | ¶î¶¨¹¤×÷µçÁ÷Ϊ10A | |
| B£® | µç³Ø³äÂúµçºó×ܵçÁ¿Îª3.6¡Á103C | |
| C£® | ×ÔÐгµµç¶¯»úµÄÄÚ×èΪ7.2¦¸ | |
| D£® | ×ÔÐгµ±£³Ö¶î¶¨¹¦ÂÊÐÐÊ»µÄ×ʱ¼äÊÇ2h |
²é¿´´ð°¸ºÍ½âÎö>>
¹ú¼ÊѧУÓÅÑ¡ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com