Question

15£®ÈçͼËùʾ£¬¾²Ö¹Ôڹ⻬ˮƽ×ÀÃæµÄ²¼´øÉÏÓÐÒ»ÖÊÁ¿Îªm=1.0kgµÄСÌú¿é£¬ËüÀë²¼´øµÄÓҶ˾àÀëΪL=0.5m£¬Ìú¿éÓë²¼´ø¼ä¶¯Ä¦²ÁÒòÊýΪ¦Ì=0.1£®ÏÖÓÃÁ¦´Ó¾²Ö¹¿ªÊ¼Ïò×óÒÔa₀=2m/s²µÄ¼ÓËٶȽ«²¼´ø´ÓÌú¿éϳé³ö£¬¼ÙÉèÌú¿é´óС²»¼Æ£¬Ìú¿é²»¹ö¶¯£¬gÈ¡10m/s²£¬Ôò£º
£¨1£©½«²¼´ø´ÓÌú¿éϳé³öÐèÒª¶à³¤Ê±¼ä£¿
£¨2£©Ìú¿éÀ뿪²¼´øÊǵÄËٶȴóС£¿
£¨3£©Èô²¼´øµÄÖÊÁ¿ÎªM=0.6Kg£¬ÔòÔÚ³é³ö²¼´øµÄ¹ý³ÌÖУ¬Ë®Æ½Á¦FËù×öµÄ¹¦Îª¶àÉÙ£¿

Answer 1

·ÖÎö £¨1£©Ìú¿éÔÚ²¼´øÉÏ»¬¶¯Ê±£¬ËùÊܵĺÏÁ¦Îª»¬¶¯Ä¦²ÁÁ¦£¬¸ù¾ÝÅ£¶ÙµÚ¶þ¶¨ÂÉÇó³öÌú¿éµÄ¼ÓËٶȣ®ÔÚ²¼´ø´ÓÌú¿éϳé³öµÄ¹ý³ÌÖУ¬²¼´øÓëÌú¿éµÄλÒÆÖ®²îΪL£¬¸ù¾ÝÔȱäËÙÖ±ÏßÔ˶¯¹«Ê½Çó³öËùÐèµÄʱ¼ä£®
£¨2£©¸ù¾ÝËÙ¶Èʱ¼ä¹«Ê½Çó³öÌú¿éÀ뿪²¼´øÊǵÄËٶȴóС£®
£¨3£©¸ù¾Ý¹¦ÄܹØϵÇó³öˮƽÁ¦FËù×öµÄ¹¦£®

½â´ð ½â£º£¨1£©ÉèÌú¿éÀ뿪²¼´øʱ£¬Ïà¶Ô×ÀÃæÒƶ¯ÁËxµÄ¾àÀ룬²¼´øÒƶ¯µÄ¾àÀëΪL+x£¬Ìú¿é»¬¶¯µÄ¼ÓËÙ¶ÈΪa£¬
ÓÉÅ£¶ÙµÚ¶þ¶¨Âɵ㺦Ìmg=ma£¬
a=¦Ìg=1m/s²
¸ù¾ÝÔ˶¯Ñ§¹«Ê½ÓУºL+x=$\frac{1}{2}{a}_{0}{t}^{2}$£¬x=$\frac{1}{2}a{t}^{2}$
½âµÃ£ºt=$\sqrt{\frac{2L}{{a}_{0}-¦Ìg}}$=$\sqrt{\frac{2¡Á0.5}{2-0.1¡Á10}}$s=1s    
¹Ê½«²¼´ø´ÓÌú¿éϳé³öÐèÒª1s£®
£¨2£©Ìú¿éÀ뿪²¼´øÊǵÄËٶȴóСΪ£ºv=at=1¡Á1=1m/s
£¨3£©Ìú¿éÀ뿪²¼´øʱ²¼´øµÄËٶȴóСΪ£ºv¡ä=a₀t=2¡Á1=2m/s
¸ù¾Ý¹¦ÄܹØϵ¿ÉµÃ£ºË®Æ½Á¦FËù×öµÄ¹¦Îª£º
W=$\frac{1}{2}m{v}^{2}$+$\frac{1}{2}Mv{¡ä}^{2}$+¦ÌmgL=$\frac{1}{2}$¡Á1¡Á1²+$\frac{1}{2}$¡Á0.6¡Á2²+0.1¡Á1¡Á10=2.7J
´ð£º£¨1£©½«²¼´ø´ÓÌú¿éϳé³öÐèÒª1sµÄʱ¼ä£®
£¨2£©Ìú¿éÀ뿪²¼´øÊǵÄËٶȴóСΪ1m/s£®
£¨3£©Èô²¼´øµÄÖÊÁ¿ÎªM=0.6Kg£¬ÔòÔÚ³é³ö²¼´øµÄ¹ý³ÌÖУ¬Ë®Æ½Á¦FËù×öµÄ¹¦Îª2.7J£®

µãÆÀ ±¾ÌâÊǶ¯Á¦Ñ§ÎÊÌ⣬֪µÀ¼ÓËÙ¶ÈÊÇÁªÏµÇ°ºóµÄÇÅÁº£®¶ÔÓÚµÚ£¨2£©ÎÊ£¬Ò²¿ÉÒÔͨ¹ý¶¯Äܶ¨Àí½øÐÐÇó½â£¬²¼´ø¶ÔÌú¿é×öµÄ¹¦µÈÓÚÌú¿é¶¯Äܵı仯£®