¡¾ÌâÄ¿¡¿Åð¼°Æ仯ºÏÎïÔÚ»¯Ñ§¹¤ÒµÖÐÓÐÖî¶àÓÃ;¡£Çë»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©ÅðÇ⻯ÄÆNaBH4ÊÇÅðµÄÖØÒª»¯ºÏÎï¡£

¢ÙNaBH4ÖÐBÔªËصĻ¯ºÏ¼ÛΪ______¡£

¹¤ÒµÉÏ¿ÉÀûÓÃÅðËá¼×õ¥B(OCH3)3ÓëÇ⻯ÄÆNaH·´Ó¦ÖƱ¸NaBH4£¬·´Ó¦µÄÁíÒ»ÖÖ²úÎïΪ¼×´¼ÄÆ£¨CH3ONa£©£¬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ______¡£

¢ÛNaBH4ÓëË®·´Ó¦Éú³ÉNaBO2ºÍH2£¬¸Ã·´Ó¦Éú³ÉµÄÑõ»¯²úÎïÓ뻹ԭ²úÎïµÄÎïÖʵÄÁ¿Ö®±ÈΪ______¡£

£¨2£©¹¤ÒµÉÏÒÔÌúÅð¿óÖ÷Òª³É·ÖΪMg2B2O5¡¤H2OºÍFe3O4£¬»¹ÓÐÉÙÁ¿¡¢FeO¡¢CaO¡¢ºÍµÈΪԭÁÏÖƱ¸µ¥ÖÊBµÄ¹¤ÒÕÁ÷³ÌÈçͼËùʾ£º

ÒÑÖª£º

½ðÊôÀë×Ó

Fe3+

Al3+

¿ªÊ¼³ÁµíµÄpH

2.7

3.1

³ÁµíÍêÈ«µÄpH

3.7

4.9

¡°½þ³ö¡±Ê±£¬½«ÌúÅð¿óʯ·ÛËéµÄÄ¿µÄΪ______¡£

ÂËÔü1µÄÖ÷Òª³É·ÖΪ______¡£

¡°¾»»¯³ýÔÓ¡±Ê±ÐèÏȼÓH2O2ÈÜÒº£¬ÆäÄ¿µÄΪ______£¬È»ºóÔÙµ÷½ÚÈÜÒºµÄpH¡Ö5.0µÄÄ¿µÄÊÇ______¡£

ÖƵõĴÖÅðÔÚÒ»¶¨Ìõ¼þÏÂÄÜÉú³ÉBI3£¬BI3¼ÓÈÈ·Ö½â¿ÉÒԵõ½´¿¾»µÄµ¥ÖÊÅð¡£ÏÖ½«´ÖÅðÖƳɵÄBI3ÍêÈ«·Ö½â£¬Éú³ÉµÄÓÃ0.30mol¡¤L£­1Na2S2O3ÈÜÒºµÎ¶¨ÖÁÖյ㣬ÏûºÄ18.00mL Na2S2O3ÈÜÒº¡£Ê¢×°Na2S2O3ÈÜÒºÓ¦ÓÃ______Ìî¡°Ëáʽ¡±»ò¡°¼îʽ¡±µÎ¶¨¹Ü£¬¸Ã´ÖÅðÑùÆ·µÄ´¿¶ÈΪ______¡£

¡¾´ð°¸¡¿+3 4NaH+B(OCH3)3£½NaBH4+3CH3ONa 1:1 Ôö´ó½Ó´¥Ãæ»ý£¬¼Ó¿ì·´Ó¦ËÙÂÊ SiO2¡¢CaSO4 ½«ÆäÖеÄÑõ»¯Îª ʹFe3£«×ª»¯ÎªFe(OH)3³Áµí¡¢Al3£«×ª»¯ÎªAl(OH)3³Áµí¶ø³ýÈ¥ ¼îʽ 97.2%

¡¾½âÎö¡¿

£¨1£©¢ÙNaBH4ÖÐNaÊÇ+1¼Û£¬HÊÇ£­1¼Û£¬ÔòBÔªËصĻ¯ºÏ¼Û£¬¸ù¾Ý»¯ºÏ¼Û´úÊýºÍΪ0£¬µÃ³öBΪ+3¼Û¡£

¹¤ÒµÉÏ¿ÉÀûÓÃÅðËá¼×õ¥B(OCH3)3ÓëÇ⻯ÄÆNaH·´Ó¦ÖƱ¸NaBH4£¬·´Ó¦µÄÁíÒ»ÖÖ²úÎïΪ¼×´¼ÄÆ£¨CH3ONa£©£¬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ4NaH+B(OCH3)3£½NaBH4+3CH3ONa ¡£

¢ÛNaBH4ÓëË®·´Ó¦Éú³ÉNaBO2ºÍH2£¬NaBH4£«2H2O£½NaBO2£«4H2¡ü£¬NaBH4ÖÐH±»Ñõ»¯£¬µÃµ½Ñõ»¯²úÎˮÖÐÇâ±»»¹Ô­£¬µÃµ½»¹Ô­²úÎ¸Ã·´Ó¦Éú³ÉµÄÑõ»¯²úÎïÓ뻹ԭ²úÎïµÄÎïÖʵÄÁ¿Ö®±ÈΪ1:1¡£

£¨2£©ÒÔÌúÅð¿ó£¨Ö÷Òª³É·ÖΪMg2B2O5¡¤H2OºÍFe3O4£¬»¹ÓÐÉÙÁ¿Fe2O3¡¢FeO¡¢CaO¡¢Al2O3ºÍSiO2µÈ£©ÎªÔ­ÁÏÖƱ¸ÅðËᣨH3BO3£©£¬ÓÉÁ÷³Ì¿ÉÖª£¬¼ÓÁòËáÈܽâÖ»ÓÐSiO2²»ÈÜ£¬Mg2B2O5¡¤H2O+2H2SO4£½2H3BO3+2MgSO4£¬CaOת»¯ÎªÎ¢ÈÜÓÚË®µÄCaSO4£¬¡°¾»»¯³ýÔÓ¡±ÐèÏȼÓH2O2ÈÜÒº£¬½«ÑÇÌúÀë×Óת»¯ÎªÌúÀë×Ó£¬µ÷½ÚÈÜÒºµÄpHԼΪ5£¬Ê¹ÌúÀë×Ó¡¢ÂÁÀë×Ó¾ùת»¯Îª³Áµí£¬ÔòÂËÔüΪÇâÑõ»¯ÂÁ¡¢ÇâÑõ»¯Ìú£¬È»ºóÕô·¢Å¨Ëõ¡¢ÀäÈ´½á¾§¡¢¹ýÂË·ÖÀë³öH3BO3¡£

¢Ù¡°½þ³ö¡±Ê±£¬½«ÌúÅð¿óʯ·ÛËéµÄÄ¿µÄΪÔö´ó½Ó´¥Ãæ»ý£¬¼Ó¿ì·´Ó¦ËÙÂÊ¡£

¢Ú¼ÓÁòËáÈܽâÖ»ÓÐSiO2²»ÈÜ£¬Mg2B2O5¡¤H2O+2H2SO4£½2H3BO3+2MgSO4£¬CaOת»¯ÎªÎ¢ÈÜÓÚË®µÄCaSO4£¬ÀûÓÃFe3O4µÄ´ÅÐÔ£¬¿É½«Æä´Ó¡°½þÔü¡±ÖзÖÀë¡£¡°½þÔü¡±Öл¹Ê£ÓàµÄÎïÖÊÊÇSiO2¡¢CaSO4£¬ÂËÔü1µÄÖ÷Òª³É·ÖΪSiO2¡¢CaSO4¡£

¢Û¡°¾»»¯³ýÔÓ¡±ÐèÏȼÓH2O2ÈÜÒº£¬ÆäÄ¿µÄΪ½«ÆäÖеÄÑõ»¯Îª£¬È»ºóÔÙµ÷½ÚÈÜÒºµÄpH¡Ö5.0µÄÄ¿µÄÊÇʹFe3£«×ª»¯ÎªFe(OH)3³Áµí¡¢Al3£«×ª»¯ÎªAl(OH)3³Áµí¶ø³ýÈ¥¡£

¢ÜNa2S2O3ÈÜÒº³Ê¼îÐÔ£¬Ó¦·ÅÔÚ¼îʽµÎ¶¨¹ÜÖУ¬Áò´úÁòËáÄƵÄÎïÖʵÄÁ¿Îª£º0.30mol¡¤L£­1¡Á0.018L=0.0054mol£¬¸ù¾Ý¹Øϵʽ£ºB¡«BI3¡«I2¡«3S2O32£­£¬Ôòn£¨B£©=n£¨S2O32£­£©=0.0018mol£¬ÅðµÄÖÊÁ¿Îª£º10.81g¡¤mol£­1¡Á0.0018mol=0.01944g£¬´ÖÅðÖÐÅðµÄº¬Á¿Îª£º¡Á100%=97.2%¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿I2ÔÚKIÈÜÒºÖдæÔÚÏÂÁÐƽºâ£ºI2(aq) + I£­(aq) I3£­(aq)¡£Ä³I2¡¢KI»ìºÏÈÜÒºÖУ¬I3£­µÄÎïÖʵÄÁ¿Å¨¶Èc(I3£­)ÓëζÈTµÄ¹ØϵÈçͼËùʾ£¨ÇúÏßÉÏÈκÎÒ»µã¶¼±íʾƽºâ״̬£©¡£ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ

A.·´Ó¦ I2(aq) + I£­(aq) I3£­(aq)µÄ¡÷H£¾0

B.״̬AÓë״̬BÏà±È£¬×´Ì¬AµÄc(I2)´ó

C.ÈôζÈΪT1¡¢T2£¬·´Ó¦µÄƽºâ³£Êý·Ö±ðΪK1¡¢K2£¬ÔòK1£¼K2

D.Èô·´Ó¦½øÐе½×´Ì¬Dʱ£¬Ò»¶¨ÓÐvÕý£¾vÄæ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿ÈçͼËùʾװÖã¬ÊÒÎÂÏÂÃܱÕÈÝÆ÷ÄÚ·Ö±ð³äÈë¿ÕÆøºÍH2£®O2µÄ»ìºÏÆøÌåÔÚ¿ÉÒƶ¯µÄ»îÈûÁ½±ß£¬ÔÚ±ê×¼×´¿öÏÂÈô½«H2£®O2µÄ»ìºÏÆøÌåµãȼÒý±¬£¬»îÈûÏÈ×󵯣¬»Ö¸´Ô­Î¶Ⱥ󣬻îÈûÓÒ»¬Í£ÁôÓÚÈÝÆ÷µÄÖÐÑ룬ÔòÔ­À´H2£®O2µÄÌå»ý±È×î½Ó½üÓÚ £¨ £©

¢Ù2£º7 ¢Ú5£º4 ¢Û4£º5 ¢Ü7£º2

A.¢Ù¢ÚB.¢Ú¢ÜC.¢Û¢ÜD.¢Ù¢Û

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿ÂÈßÁ¸ñÀ×ÊÇÒ»ÖÖÓÃÓÚÒÖÖÆѪС°å¾Û¼¯µÄÒ©Î¸ù¾ÝÔ­ÁϵIJ»Í¬£¬¸ÃÒ©ÎïµÄºÏ³É·Ïßͨ³£ÓÐÁ½Ìõ£¬ÆäÖÐÒÔ2¡ªÂȱ½¼×ȩΪԭÁϵĺϳÉ·ÏßÈçÏ£º

£¨1£©D¡úEËùÐèXÎïÖʵĽṹ¼òʽ£º____________¡£

£¨2£©C¡úD·´Ó¦Éú³ÉDµÄ²úÁ¿Æ«µÍ£¬Çë½âÊÍÔ­Òò£º______________________________________£¨3£©Ð´³öC¾ÛºÏ³É¸ß·Ö×Ó»¯ºÏÎïµÄ·½³Ìʽ___________________________________£»

£¨4£©AÄÜת»¯³ÉF·Ö×ÓC7H7NO2£¬Ð´³öͬʱ·ûºÏÏÂÁÐÌõ¼þFµÄËùÓÐͬ·ÖÒì¹¹ÌåµÄ½á¹¹¼òʽ£º__________¡£

¢Ùºì¹â¹âÆ×±íÃ÷·Ö×ÓÖк¬ÓÐ-COO-½á¹¹£»

¢Ú1H-NMRÆ×ÏÔʾ·Ö×ÓÖк¬Óб½»·£¬ÇÒ±½»·ÉÏÓÐÈýÖÖ²»Í¬»¯Ñ§»·¾³µÄÇâÔ­×Ó¡£

£¨5£©ÒÑÖª£º

д³öÓÉÒÒÏ©¡¢¼×´¼ÎªÓлúÔ­ÁÏÖƱ¸»¯ºÏÎïµÄºÏ³É·ÏßÁ÷³Ìͼ_____________________£¨ÎÞ»úÊÔ¼ÁÈÎÑ¡£©¡£ºÏ³É·ÏßÁ÷³ÌͼʾÀýÈçÏ£º

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿Ä³º¬ÑõÓлú»¯ºÏÎï¿ÉÒÔ×÷ΪÎÞǦÆûÓ͵Ŀ¹±¬Õð¼Á£¬º¬CµÄÖÊÁ¿·ÖÊýΪ68.2%£¬º¬HµÄÖÊÁ¿·ÖÊýΪ13.6%¡£

£¨1£©Çó³ö¸ÃÓлú»¯ºÏÎïµÄ×î¼òʽ£¨ÒªÇóд³ö¼ÆËã¹ý³Ì£©¡£___________

£¨2£©________£¨Ìî¡°ÄÜ¡±»ò¡°²»ÄÜ¡±£©È·¶¨¸ÃÓлú»¯ºÏÎïµÄ·Ö×Óʽ£¬ÈôÄÜÈ·¶¨£¬¸ÃÓлúÎïµÄ·Ö×ÓʽΪ________________£¬ÀíÓÉÊÇ______________

£¨3£©ºìÍâ¹âÆ׺ͺ˴Ź²ÕñÇâÆ×ÏÔʾ¸Ã·Ö×ÓÖÐÓÐ4¸ö¼×»ù£¬Çëд³öÆä½á¹¹¼òʽ___________

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿ÔÚ0.1mol/LµÄCH3COOHÈÜÒºÖдæÔÚÈçϵçÀëƽºâ£ºCH3COOHCH3COO-+H+£¬¶ÔÓÚ¸Ãƽºâ£¬ÏÂÁÐÐðÊöÕýÈ·µÄÊÇ ( )

A.¼ÓÈëÉÙÁ¿NaOH¹ÌÌ壬ƽºâÏòÕý·´Ó¦·½ÏòÒƶ¯

B.¼ÓË®£¬·´Ó¦ËÙÂÊÔö´ó£¬Æ½ºâÏòÄæ·´Ó¦·½ÏòÒƶ¯

C.µÎ¼ÓÉÙÁ¿0.1mol/L HClÈÜÒº£¬ÈÜÒºÖÐc(H+)¼õÉÙ

D.¼ÓÈëÉÙÁ¿CH3COONa¹ÌÌ壬ƽºâÏòÕý·´Ó¦·½ÏòÒƶ¯

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿Ò»¡¢£¨1£©ÁòËáÍ­¾§ÌåµÄÈܽâ¶ÈËä´ó£¬µ«Èܽâ¹ý³Ì½ÏÂý£¬ÊµÑéÊÒ³£ÓÃÈÈË®ÅäÖÆÒÔ¼Ó¿ìÈܽâËÙÂÊ£¬µ«³£³£»á²úÉú»ë×Ç£¬ÇëÓÃÎÄ×Ö¼òҪ˵Ã÷Ô­Òò_______________¡£

£¨2£©Ï¡Na2SÈÜÒºÓÐÒ»ÖÖ¸¯ÂÑÆø棬¼ÓÈëAlCl3ÈÜÒººó£¬¸¯ÂÑÆøζ¼Ó¾ç£¬ÓÃÀë×Ó·½³Ìʽ±íʾÆøζ¼Ó¾ç¹ý³ÌËù·¢ÉúµÄ»¯Ñ§·´Ó¦______________¡£

¶þ¡¢ÒÀ¾ÝÑõ»¯»¹Ô­·´Ó¦£ºMnO4-+5Fe2++8H+ = Mn2++5Fe3++4H2O£¬Óû²ÉÓõζ¨µÄ·½·¨²â¶¨FeSO4µÄÖÊÁ¿·ÖÊý£¬ÊµÑé²½ÖèÈçÏ£º¢Ù³ÆÁ¿ÂÌ·¯ÑùÆ·£¬Åä³É100 mL´ý²âÈÜÒº£¬¢ÚÈ¡Ò»¶¨Ìå»ý´ý²âÒºÖÃÓÚ׶ÐÎÆ¿ÖУ¬²¢¼ÓÈëÒ»¶¨Á¿µÄÁòËᣬ¢Û½«±ê׼Ũ¶ÈµÄKMnO4ÈÜҺװÈëµÎ¶¨¹ÜÖУ¬µ÷½ÚÒºÃæÖÁa mL´¦£¬¢ÜµÎ¶¨´ý²âÒºÖÁµÎ¶¨ÖÕµãʱ£¬µÎ¶¨¹ÜµÄÒºÃæ¶ÁÊýb mL£¬¢ÝÖظ´µÎ¶¨2¡«3´Î¡£

£¨1£©ÈçºÎÖªµÀµÎ¶¨µ½´ïÖյ㣿__________¡£ÏÂÁвÙ×÷»áµ¼Ö²ⶨ½á¹ûÆ«µÍµÄÊÇ_______¡£

A£®Ê¢±ê×¼ÈÜÒºµÄµÎ¶¨¹ÜÓÃÕôÁóˮϴµÓºóδÓñê×¼ÒºÈóÏ´¾Í×°ÒºµÎ¶¨

B£®×¶ÐÎÆ¿ÓÃÕôÁóˮϴµÓºóδÓôý²âÒºÈóÏ´

C£®¶ÁÈ¡±ê×¼Òº¶ÁÊýʱ£¬µÎ¶¨Ç°Æ½ÊÓ£¬µÎ¶¨µ½ÖÕµãºó¸©ÊÓ

D£®µÎ¶¨Ç°µÎ¶¨¹Ü¼â×ì´¦ÓÐÆøÅÝδÅųý£¬µÎ¶¨ºóÆøÅÝÏûʧ

£¨2£©ÏÂÁÐÿÖÖÁ¿Æ÷µÄÊýÁ¿²»ÏÞ£¬ÔÚÉÏÊöʵÑéÖУ¬±ØÐëʹÓõÄÓÐ____________£»

A£®ÍÐÅÌÌìƽ B£®Á¿Í² C£®¼îʽµÎ¶¨¹Ü D£®ËáʽµÎ¶¨¹Ü

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿Ä³Î¶ÈÏ£¬Å¨¶È¶¼ÊÇ1 mol¡¤L£­1µÄÁ½ÖÖÆøÌåX2ºÍY2£¬ÔÚÃܱÕÈÝÆ÷Öз´Ó¦Éú³ÉÆøÌåZ¡£·´Ó¦2 minºó£¬²âµÃ²Î¼Ó·´Ó¦µÄX2Ϊ0.6 mol¡¤L£­1£¬ÓÃY2µÄ±ä»¯±íʾµÄ·´Ó¦ËÙÂÊv(Y2)£½0.1 mol¡¤L£­1¡¤ min£­1£¬Éú³ÉµÄc(Z)Ϊ0.4 mol¡¤L£­1£¬Ôò¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ( )

A.X2£«2Y22XY2B.3X2£«Y22X3Y

C.X2£«3Y22XY3D.2X2£«Y22X2Y

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿ÔÚ°±Ë®ÖдæÔÚµçÀëƽºâ£ºNH3¡¤H2O NH4+ + OH£­£¬ÏÂÁÐÇé¿öÄÜÒýÆðµçÀëƽºâÏòÓÒÒƶ¯µÄÓÐ( )¡£

¢Ù¼ÓNH4Cl¹ÌÌå ¢Ú¼ÓNaOHÈÜÒº ¢ÛͨHCl ¢Ü¼ÓCH3COOHÈÜÒº ¢Ý¼ÓË®

A.¢Ù¢Û¢ÝB.¢Ù¢Ü¢ÝC.¢Ù¢Ú¢ÜD.¢Û¢Ü¢Ý

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸