0  433073  433081  433087  433091  433097  433099  433103  433109  433111  433117  433123  433127  433129  433133  433139  433141  433147  433151  433153  433157  433159  433163  433165  433167  433168  433169  433171  433172  433173  433175  433177  433181  433183  433187  433189  433193  433199  433201  433207  433211  433213  433217  433223  433229  433231  433237  433241  433243  433249  433253  433259  433267  447090 

7. (2010·南京模拟) So far I haven’t adapted to the fast ______ of the modern life in Tokyo.

A. step      B. style     C. pace        D. manner

试题详情

6.(2010·济南模拟)Please read the _______ on the bottle and take the right amount of medicine.

A. explanations    B. descriptions   C. instructions    D. introductions

试题详情

5.(2010·芜湖模拟)In the     of proof,  the police could not take action against the man.

A.lack    B.shortage    C.absence     D.failure

试题详情

4.(2010·沈阳模拟) Despite such a big difference in ____ towards what one eats, there is no doubt that people

in the west regard the Chinese food as something special.

A. point     B. idea   C. attitude      D. sight

试题详情

3.(2010·银川模拟)Although I had read the book assigned by the professor several times , it didn’t make any _____  to me.

A.meaning    B.importance     C.sense    D.significance

试题详情

2.(2010·温州模拟)   Typhoon Morakot has caused great _________ to the local economies in Wenzhou.

            A. injury      B. wound    C. ruin      D. damage

试题详情

1.(2010·天津模拟)The increase in home computers means that families have much easier     to information.

A.measure      B.access     C.way    D.method

试题详情

9.设ab∈R,记max{ab}=函数f(x)=max{|x+1|,|x-2|}(x∈R)的最小值是________.

试题详情

8.(2009·南昌二调)函数f(x)=,若f(4x1)+f(4x2)=1,x1>1,x2>1,则f(x1·x2)的最小值为( )

A.                             B.

C.2                            D.

答案:B

解析:依题意得f(x)=1-,

1-+1-=1,

由此解得log2x2=,log2(x2x1)=log2x2+log2x1=+log2x1=+log2x1=-2++(log2x1+1)≥-2+2=2,故f(x1x2)=1-≥1-=,f(x1·x2)的最小值是,故选B.

试题详情

7.在区间[1.5,3]上,函数f(x)=x2+bx+c与函数g(x)=x+同时取到相同的最小值,则函数f(x)在区间[1.5,3]上的最大值为( )

A.8                            B.6

C.5                            D.4

答案:D

解析:g(x)=x-1++1≥2+1=3,当且仅当x=2时,g(x)min=3,

f(x)=(x-2)2+3.

∴在区间[1.5,3]上,f(x)maxf(3)=4.

故选D.

试题详情


同步练习册答案
闂傚倷鑳舵灙濡ょ姴绻橀獮蹇涙晸閿燂拷 闂傚倸鍊搁崐鎼佸磻婵犲洤绠柨鐕傛嫹